#### Question 1 - Outliers are present in below data Min 0 Q1 15 Median 25 Q3 45 Max 88

IQR = Q3 - Q1 = 45 - 15 = 30 1.5*IQR = 45 Lower limit for outliers = Q1 - 1.5 * IQR (-30) and higher limits for outliers is 1.5 * IQR (90) As no value in dataset is beyond (-30, 90) we have no outliers

#### Question 2 - Calculate semi interquartile range for dataset with five number summary as {min -20 Q1 0 Median 20 Q3 100 Max 1000}

Inter quartile range IQR = Q3 - Q1 = 100 Semi IQR = 50

#### Question 3 - Distance between Q1 and Median is always same as distance between Q3 and Maximum value

This is not always true