Question 1 - Mean and number of trials of a particular binomial distribution is known as 3 and 60 respectively. Standard deviation of this distribution is

For binomial distribution mean = np and variance = npq 60*p = 3 So p = 1/20 and q = 19/20 Variance = 60*1/20*19/20 = 57/20 and standard deviation = SQRT(57/20) = 1.69

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